Example 1

An 8 inch outlet is welded into a 24 inch header. The header material is API 5LX 46 with ⁵/₁₆ inch wall. The outlet is API 5L Grade B (Seamless) Sched. 40 with 0.322 inch wall. The working pressure is 650 PSI. The Class Location is 1. The joint efficiency is 1.00. The temperature is 100°F. Design Factors F=0.60, E=1.00, T=1.00. For dimensions see Figure for Example 1, Appendix 14-G.

Header:

Nominal wall thickness:

Outlet:

Nominal wall thickess:

Reinforcement required.

A_R = d × t = 7.981 × 0.283 = 2.26 square inch

Reinforcement provided:

A₁ = (H-t)d = 0.029 × 7.981 = 0.23 square inch

Effective area in outlet:

Height (L) 2½ B + M (assume ¼ inch pad) = 2½ × 0.322 + 0.25 = 1.05 inches or 2½ H = 2.5 × 0.312 = 0.78 inch. Use 0.78 inch.

A₂ = 2(B-t_b)L = 2 × 0.189 × 0.78 = 0.295 sq. in.

This must be multiplied by 35000/46000

Required area A₃ = A_R - A₁ - A₂ = 2.26 - 0.23 - 0.22 = 1.81 sq. in.

Use reinf. pl. ¼ inch thick (minimum practicable) × 15.5 inch diameter.

Area (15.50 - 8.62) × 0.25 = 1.72 sq. in.

Fillet welds (assuming two ¼ inch welds each side)

0.25 × 0.25 × 0.50 × 2 × 2 = 0.12 sq. in.

Example 2

A 16 inch outlet is welded into a 24 inch header. The header material is API 5LX46 with ⁵/₁₆ inch wall. The outlet is API 5L Grade B (Seamless) Sched. 20 with 0.312 wall. The working pressure is 650 PSI. The Class Location is 1. The reinforcement must be of the complete encirclement type. The joint efficiency is 1.00. The temperature is 100°F. Design Factors F=0.60, E=1.00, T=1.00. For dimensions see Figure for Example 2 in Appendix 14-G.

Header:

Nominal wall thickness: